Base | Representation |
---|---|
bin | 10000001010101100110… |
… | …100110110111101001011 |
3 | 10221012200120120120000212 |
4 | 100022230310312331023 |
5 | 121200312240200412 |
6 | 2210215321151335 |
7 | 143160433351463 |
oct | 20125464667513 |
9 | 3835616516025 |
10 | 1111001100107 |
11 | 39919a180368 |
12 | 15b3a002b54b |
13 | 809c7cc9572 |
14 | 3bab6582ba3 |
15 | 1dd766ab222 |
hex | 102acd36f4b |
1111001100107 has 2 divisors, whose sum is σ = 1111001100108. Its totient is φ = 1111001100106.
The previous prime is 1111001100101. The next prime is 1111001100151. The reversal of 1111001100107 is 7010011001111.
It is a weak prime.
It is an emirp because it is prime and its reverse (7010011001111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111001100107 - 24 = 1111001100091 is a prime.
It is a super-2 number, since 2×11110011001072 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1111001100091 and 1111001100100.
It is not a weakly prime, because it can be changed into another prime (1111001100101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555500550053 + 555500550054.
It is an arithmetic number, because the mean of its divisors is an integer number (555500550054).
Almost surely, 21111001100107 is an apocalyptic number.
1111001100107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111001100107 is an equidigital number, since it uses as much as digits as its factorization.
1111001100107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 1111001100107 its reverse (7010011001111), we get a palindrome (8121012101218).
The spelling of 1111001100107 in words is "one trillion, one hundred eleven billion, one million, one hundred thousand, one hundred seven".
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