Base | Representation |
---|---|
bin | 1010000110101100000001… |
… | …0000111101101110010011 |
3 | 1110100002212202221121002111 |
4 | 2201223000100331232103 |
5 | 2424011300320200201 |
6 | 35343511343130151 |
7 | 2224446301124413 |
oct | 241530020755623 |
9 | 43302782847074 |
10 | 11110011100051 |
11 | 35a38026a0716 |
12 | 12b52402a3957 |
13 | 627892009426 |
14 | 2a5a28008643 |
15 | 143ee4745b51 |
hex | a1ac043db93 |
11110011100051 has 2 divisors, whose sum is σ = 11110011100052. Its totient is φ = 11110011100050.
The previous prime is 11110011100043. The next prime is 11110011100057. The reversal of 11110011100051 is 15000111001111.
It is a strong prime.
It is an emirp because it is prime and its reverse (15000111001111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11110011100051 - 23 = 11110011100043 is a prime.
It is a super-2 number, since 2×111100111000512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11110011100057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005550025 + 5555005550026.
It is an arithmetic number, because the mean of its divisors is an integer number (5555005550026).
Almost surely, 211110011100051 is an apocalyptic number.
11110011100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110011100051 is an equidigital number, since it uses as much as digits as its factorization.
11110011100051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 13.
Adding to 11110011100051 its reverse (15000111001111), we get a palindrome (26110122101162).
The spelling of 11110011100051 in words is "eleven trillion, one hundred ten billion, eleven million, one hundred thousand, fifty-one".
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