1111012100113 has 2 divisors, whose sum is σ = 1111012100114. Its totient is φ = 1111012100112.

The previous prime is 1111012100089. The next prime is 1111012100161. The reversal of 1111012100113 is 3110012101111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 958581981184 + 152430118929 = 979072^2 + 390423^2 .

It is an emirp because it is prime and its reverse (3110012101111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111012100113 is a prime.

It is a super-2 number, since 2×1111012100113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111012100093 and 1111012100102.

It is not a weakly prime, because it can be changed into another prime (1111012104113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555506050056 + 555506050057.

It is an arithmetic number, because the mean of its divisors is an integer number (555506050057).

Almost surely, 2^{1111012100113} is an apocalyptic number.

It is an amenable number.

1111012100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111012100113 is an equidigital number, since it uses as much as digits as its factorization.

1111012100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1111012100113 its reverse (3110012101111), we get a palindrome (4221024201224).

The spelling of 1111012100113 in words is "one trillion, one hundred eleven billion, twelve million, one hundred thousand, one hundred thirteen".