11110211100113 has 2 divisors, whose sum is σ = 11110211100114. Its totient is φ = 11110211100112.

The previous prime is 11110211100097. The next prime is 11110211100137. The reversal of 11110211100113 is 31100111201111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10768819801744 + 341391298369 = 3281588^2 + 584287^2 .

It is an emirp because it is prime and its reverse (31100111201111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11110211100113 - 2⁴ = 11110211100097 is a prime.

It is a super-2 number, since 2×11110211100113² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11110211100173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555105550056 + 5555105550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5555105550057).

Almost surely, 2^{11110211100113} is an apocalyptic number.

It is an amenable number.

11110211100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110211100113 is an equidigital number, since it uses as much as digits as its factorization.

11110211100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 14.

Adding to 11110211100113 its reverse (31100111201111), we get a palindrome (42210322301224).

The spelling of 11110211100113 in words is "eleven trillion, one hundred ten billion, two hundred eleven million, one hundred thousand, one hundred thirteen".