Base | Representation |
---|---|
bin | 10000001010101110000… |
… | …001111011000110011001 |
3 | 10221012201222120221001101 |
4 | 100022232001323012121 |
5 | 121200332423132134 |
6 | 2210221322151401 |
7 | 143161100151562 |
oct | 20125601730631 |
9 | 3835658527041 |
10 | 1111021302169 |
11 | 3991aa619489 |
12 | 15b3a6952561 |
13 | 809cc25094c |
14 | 3bab9121169 |
15 | 1dd7834be14 |
hex | 102ae07b199 |
1111021302169 has 2 divisors, whose sum is σ = 1111021302170. Its totient is φ = 1111021302168.
The previous prime is 1111021302119. The next prime is 1111021302191. The reversal of 1111021302169 is 9612031201111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1100736705600 + 10284596569 = 1049160^2 + 101413^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111021302169 - 229 = 1110484431257 is a prime.
It is a super-2 number, since 2×11110213021692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111021302119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555510651084 + 555510651085.
It is an arithmetic number, because the mean of its divisors is an integer number (555510651085).
Almost surely, 21111021302169 is an apocalyptic number.
It is an amenable number.
1111021302169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111021302169 is an equidigital number, since it uses as much as digits as its factorization.
1111021302169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 1111021302169 in words is "one trillion, one hundred eleven billion, twenty-one million, three hundred two thousand, one hundred sixty-nine".
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