11110224113 has 2 divisors, whose sum is σ = 11110224114. Its totient is φ = 11110224112.

The previous prime is 11110224067. The next prime is 11110224161. The reversal of 11110224113 is 31142201111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6579318769 + 4530905344 = 81113^2 + 67312^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110224113 - 2¹⁸ = 11109961969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11110224091 and 11110224100.

It is not a weakly prime, because it can be changed into another prime (11110221113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555112056 + 5555112057.

It is an arithmetic number, because the mean of its divisors is an integer number (5555112057).

Almost surely, 2^11110224113 is an apocalyptic number.

It is an amenable number.

11110224113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110224113 is an equidigital number, since it uses as much as digits as its factorization.

11110224113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11110224113 its reverse (31142201111), we get a palindrome (42252425224).

The spelling of 11110224113 in words is "eleven billion, one hundred ten million, two hundred twenty-four thousand, one hundred thirteen".