Base | Representation |
---|---|
bin | 10100101100011101… |
… | …10100100100001001 |
3 | 1001200022011220201222 |
4 | 22112032310210021 |
5 | 140223230333223 |
6 | 5034250251425 |
7 | 542216601323 |
oct | 122616644411 |
9 | 31608156658 |
10 | 11110402313 |
11 | 479159477a |
12 | 21a0a26b75 |
13 | 1080a70b6a |
14 | 77580c613 |
15 | 4505eb0c8 |
hex | 2963b4909 |
11110402313 has 2 divisors, whose sum is σ = 11110402314. Its totient is φ = 11110402312.
The previous prime is 11110402297. The next prime is 11110402409. The reversal of 11110402313 is 31320401111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10388297929 + 722104384 = 101923^2 + 26872^2 .
It is a cyclic number.
It is not a de Polignac number, because 11110402313 - 24 = 11110402297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11110402291 and 11110402300.
It is not a weakly prime, because it can be changed into another prime (11110404313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555201156 + 5555201157.
It is an arithmetic number, because the mean of its divisors is an integer number (5555201157).
Almost surely, 211110402313 is an apocalyptic number.
It is an amenable number.
11110402313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110402313 is an equidigital number, since it uses as much as digits as its factorization.
11110402313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11110402313 its reverse (31320401111), we get a palindrome (42430803424).
The spelling of 11110402313 in words is "eleven billion, one hundred ten million, four hundred two thousand, three hundred thirteen".
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