11111000000003 has 2 divisors, whose sum is σ = 11111000000004. Its totient is φ = 11111000000002.

The previous prime is 11110999999969. The next prime is 11111000000143. The reversal of 11111000000003 is 30000000011111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11111000000003 - 2¹⁴ = 11110999983619 is a prime.

It is a super-3 number, since 3×11111000000003³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11111000000203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500000001 + 5555500000002.

It is an arithmetic number, because the mean of its divisors is an integer number (5555500000002).

Almost surely, 2^{11111000000003} is an apocalyptic number.

11111000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111000000003 is an equidigital number, since it uses as much as digits as its factorization.

11111000000003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 11111000000003 its reverse (30000000011111), we get a palindrome (41111000011114).

The spelling of 11111000000003 in words is "eleven trillion, one hundred eleven billion, three", and thus it is an aban number.