11111000000153 has 2 divisors, whose sum is σ = 11111000000154. Its totient is φ = 11111000000152.

The previous prime is 11111000000147. The next prime is 11111000000203. The reversal of 11111000000153 is 35100000011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8470270999129 + 2640729001024 = 2910373^2 + 1625032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111000000153 is a prime.

It is not a weakly prime, because it can be changed into another prime (11111000000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500000076 + 5555500000077.

It is an arithmetic number, because the mean of its divisors is an integer number (5555500000077).

Almost surely, 2^{11111000000153} is an apocalyptic number.

It is an amenable number.

11111000000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111000000153 is an equidigital number, since it uses as much as digits as its factorization.

11111000000153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 11111000000153 its reverse (35100000011111), we get a palindrome (46211000011264).

The spelling of 11111000000153 in words is "eleven trillion, one hundred eleven billion, one hundred fifty-three", and thus it is an aban number.