Base | Representation |
---|---|
bin | 1010000110101111101100… |
… | …1101101101000001101011 |
3 | 1110100012102200221001022012 |
4 | 2201223323031231001223 |
5 | 2424020312011212341 |
6 | 35344153432550135 |
7 | 2224512640365131 |
oct | 241537315550153 |
9 | 43305380831265 |
10 | 11111000100971 |
11 | 35a416a991751 |
12 | 12b547755234b |
13 | 6279bbb95084 |
14 | 2a5abd4d1751 |
15 | 1440514a30eb |
hex | a1afb36d06b |
11111000100971 has 2 divisors, whose sum is σ = 11111000100972. Its totient is φ = 11111000100970.
The previous prime is 11111000100929. The next prime is 11111000101027. The reversal of 11111000100971 is 17900100011111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11111000100971 is a prime.
It is not a weakly prime, because it can be changed into another prime (11111000100071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500050485 + 5555500050486.
It is an arithmetic number, because the mean of its divisors is an integer number (5555500050486).
Almost surely, 211111000100971 is an apocalyptic number.
11111000100971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111000100971 is an equidigital number, since it uses as much as digits as its factorization.
11111000100971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 23.
The spelling of 11111000100971 in words is "eleven trillion, one hundred eleven billion, one hundred thousand, nine hundred seventy-one".
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