Base | Representation |
---|---|
bin | 1010000110101111101101… |
… | …0001001011001111010001 |
3 | 1110100012102202122021211122 |
4 | 2201223323101023033101 |
5 | 2424020312224324103 |
6 | 35344153504252025 |
7 | 2224512651205541 |
oct | 241537321131721 |
9 | 43305382567748 |
10 | 11111001011153 |
11 | 35a417045356a |
12 | 12b5477911015 |
13 | 6279bc123444 |
14 | 2a5abd68b321 |
15 | 1440515d2b38 |
hex | a1afb44b3d1 |
11111001011153 has 2 divisors, whose sum is σ = 11111001011154. Its totient is φ = 11111001011152.
The previous prime is 11111001011111. The next prime is 11111001011171. The reversal of 11111001011153 is 35111010011111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10875069321169 + 235931689984 = 3297737^2 + 485728^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111001011153 - 216 = 11111000945617 is a prime.
It is not a weakly prime, because it can be changed into another prime (11111001091153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555500505576 + 5555500505577.
It is an arithmetic number, because the mean of its divisors is an integer number (5555500505577).
Almost surely, 211111001011153 is an apocalyptic number.
It is an amenable number.
11111001011153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111001011153 is an equidigital number, since it uses as much as digits as its factorization.
11111001011153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15, while the sum is 17.
Adding to 11111001011153 its reverse (35111010011111), we get a palindrome (46222011022264).
The spelling of 11111001011153 in words is "eleven trillion, one hundred eleven billion, one million, eleven thousand, one hundred fifty-three".
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