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111110022020147 is a prime number
BaseRepresentation
bin11001010000110111010001…
…011001001011110000110011
3112120102000101110210220221012
4121100313101121023300303
5104030411311114121042
61032151123420021135
732255301632150663
oct3120672131136063
9476360343726835
10111110022020147
113244854a886267
1210565a496917ab
1349cc8264a6967
141d61a7a4601a3
15cca35ee70e82
hex650dd164bc33

111110022020147 has 2 divisors, whose sum is σ = 111110022020148. Its totient is φ = 111110022020146.

The previous prime is 111110022020119. The next prime is 111110022020197. The reversal of 111110022020147 is 741020220011111.

It is a weak prime.

It is an emirp because it is prime and its reverse (741020220011111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111110022020147 - 232 = 111105727052851 is a prime.

It is not a weakly prime, because it can be changed into another prime (111110022020197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555011010073 + 55555011010074.

It is an arithmetic number, because the mean of its divisors is an integer number (55555011010074).

Almost surely, 2111110022020147 is an apocalyptic number.

111110022020147 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110022020147 is an equidigital number, since it uses as much as digits as its factorization.

111110022020147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 111110022020147 its reverse (741020220011111), we get a palindrome (852130242031258).

The spelling of 111110022020147 in words is "one hundred eleven trillion, one hundred ten billion, twenty-two million, twenty thousand, one hundred forty-seven".