Base | Representation |
---|---|
bin | 10000001010110010101… |
… | …111010100110110111011 |
3 | 10221012221111021002120011 |
4 | 100022302233110312323 |
5 | 121201013140004034 |
6 | 2210233223442351 |
7 | 143163046555114 |
oct | 20126257246673 |
9 | 3835844232504 |
10 | 1111100313019 |
11 | 399240184504 |
12 | 15b4092b63b7 |
13 | 80a12725a28 |
14 | 3bac580b20b |
15 | 1dd80257864 |
hex | 102b2bd4dbb |
1111100313019 has 2 divisors, whose sum is σ = 1111100313020. Its totient is φ = 1111100313018.
The previous prime is 1111100312999. The next prime is 1111100313023. The reversal of 1111100313019 is 9103130011111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111100313019 is a prime.
It is a super-2 number, since 2×11111003130192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111100313919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555550156509 + 555550156510.
It is an arithmetic number, because the mean of its divisors is an integer number (555550156510).
Almost surely, 21111100313019 is an apocalyptic number.
1111100313019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111100313019 is an equidigital number, since it uses as much as digits as its factorization.
1111100313019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 22.
The spelling of 1111100313019 in words is "one trillion, one hundred eleven billion, one hundred million, three hundred thirteen thousand, nineteen".
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