Base | Representation |
---|---|
bin | 11001010000110111010110… |
… | …101001001110100100000010 |
3 | 112120102000121121120110020111 |
4 | 121100313112221032210002 |
5 | 104030412001142041002 |
6 | 1032151140244101534 |
7 | 32255304052005361 |
oct | 3120672651164402 |
9 | 476360547513214 |
10 | 111110110112002 |
11 | 32448595583a51 |
12 | 10565a730948aa |
13 | 49cc83b80b211 |
14 | 1d61a880317d8 |
15 | cca367a723d7 |
hex | 650dd6a4e902 |
111110110112002 has 4 divisors (see below), whose sum is σ = 166665165168006. Its totient is φ = 55555055056000.
The previous prime is 111110110111969. The next prime is 111110110112021. The reversal of 111110110112002 is 200211011011111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 82983008469001 + 28127101643001 = 9109501^2 + 5303499^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27777527527999 + ... + 27777527528002.
Almost surely, 2111110110112002 is an apocalyptic number.
111110110112002 is a deficient number, since it is larger than the sum of its proper divisors (55555055056004).
111110110112002 is an equidigital number, since it uses as much as digits as its factorization.
111110110112002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55555055056003.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 111110110112002 its reverse (200211011011111), we get a palindrome (311321121123113).
The spelling of 111110110112002 in words is "one hundred eleven trillion, one hundred ten billion, one hundred ten million, one hundred twelve thousand, two".
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