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11111020202013 = 33839670165537
BaseRepresentation
bin1010000110101111110001…
…1010011000100000011101
31110100012111002202021202020
42201223330122120200131
52424020332132431023
635344155431450353
72224513303264554
oct241537432304035
943305432667666
1011111020202013
1135a4180270986
1212b54822269b9
136279c30b2494
142a5ac2044d9b
15144053123de3
hexa1afc69881d

11111020202013 has 8 divisors (see below), whose sum is σ = 14853374266368. Its totient is φ = 7388006469504.

The previous prime is 11111020201997. The next prime is 11111020202041. The reversal of 11111020202013 is 31020202011111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11111020202013 - 24 = 11111020201997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11111020201983 and 11111020202001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111020204013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4835081620 + ... + 4835083917.

It is an arithmetic number, because the mean of its divisors is an integer number (1856671783296).

Almost surely, 211111020202013 is an apocalyptic number.

It is an amenable number.

11111020202013 is a deficient number, since it is larger than the sum of its proper divisors (3742354064355).

11111020202013 is an equidigital number, since it uses as much as digits as its factorization.

11111020202013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9670165923.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 11111020202013 its reverse (31020202011111), we get a palindrome (42131222213124).

The spelling of 11111020202013 in words is "eleven trillion, one hundred eleven billion, twenty million, two hundred two thousand, thirteen".

Divisors: 1 3 383 1149 9670165537 29010496611 3703673400671 11111020202013