Base | Representation |
---|---|
bin | 11001010000111000010001… |
… | …101001010110011101111011 |
3 | 112120102010011121012222110111 |
4 | 121100320101221112131323 |
5 | 104030421013100000443 |
6 | 1032151422404525151 |
7 | 32255340431632516 |
oct | 3120702151263573 |
9 | 476363147188414 |
10 | 111111100000123 |
11 | 32448a53320603 |
12 | 105660aa6b07b7 |
13 | 49cc968917932 |
14 | 1d61b3d6a9d7d |
15 | cca3c490769d |
hex | 650e11a5677b |
111111100000123 has 2 divisors, whose sum is σ = 111111100000124. Its totient is φ = 111111100000122.
The previous prime is 111111100000099. The next prime is 111111100000129. The reversal of 111111100000123 is 321000001111111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111111100000123 is a prime.
It is a super-3 number, since 3×1111111000001233 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (111111100000129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555550000061 + 55555550000062.
It is an arithmetic number, because the mean of its divisors is an integer number (55555550000062).
Almost surely, 2111111100000123 is an apocalyptic number.
111111100000123 is a deficient number, since it is larger than the sum of its proper divisors (1).
111111100000123 is an equidigital number, since it uses as much as digits as its factorization.
111111100000123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 111111100000123 its reverse (321000001111111), we get a palindrome (432111101111234).
The spelling of 111111100000123 in words is "one hundred eleven trillion, one hundred eleven billion, one hundred million, one hundred twenty-three", and thus it is an aban number.
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