11111110020193 has 2 divisors, whose sum is σ = 11111110020194. Its totient is φ = 11111110020192.

The previous prime is 11111110020163. The next prime is 11111110020239. The reversal of 11111110020193 is 39102001111111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9828275160064 + 1282834860129 = 3135008^2 + 1132623^2 .

It is an emirp because it is prime and its reverse (39102001111111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111110020193 is a prime.

It is not a weakly prime, because it can be changed into another prime (11111110020163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555555010096 + 5555555010097.

It is an arithmetic number, because the mean of its divisors is an integer number (5555555010097).

Almost surely, 2^{11111110020193} is an apocalyptic number.

It is an amenable number.

11111110020193 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111110020193 is an equidigital number, since it uses as much as digits as its factorization.

11111110020193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 22.

The spelling of 11111110020193 in words is "eleven trillion, one hundred eleven billion, one hundred ten million, twenty thousand, one hundred ninety-three".