Base | Representation |
---|---|
bin | 11001010000111000010010… |
… | …001111100010110011010001 |
3 | 112120102010012022001122022221 |
4 | 121100320102033202303101 |
5 | 104030421023130341423 |
6 | 1032151423403301041 |
7 | 32255340613012141 |
oct | 3120702217426321 |
9 | 476363168048287 |
10 | 111111110012113 |
11 | 32448a58a39782 |
12 | 105660b1b1a781 |
13 | 49cc96aa11aa3 |
14 | 1d61b40b54921 |
15 | cca3c5733e5d |
hex | 650e123e2cd1 |
111111110012113 has 2 divisors, whose sum is σ = 111111110012114. Its totient is φ = 111111110012112.
The previous prime is 111111110012081. The next prime is 111111110012173. The reversal of 111111110012113 is 311210011111111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86742995942464 + 24368114069649 = 9313592^2 + 4936407^2 .
It is a cyclic number.
It is not a de Polignac number, because 111111110012113 - 25 = 111111110012081 is a prime.
It is not a weakly prime, because it can be changed into another prime (111111110012173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555555006056 + 55555555006057.
It is an arithmetic number, because the mean of its divisors is an integer number (55555555006057).
Almost surely, 2111111110012113 is an apocalyptic number.
It is an amenable number.
111111110012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
111111110012113 is an equidigital number, since it uses as much as digits as its factorization.
111111110012113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 16.
Adding to 111111110012113 its reverse (311210011111111), we get a palindrome (422321121123224).
The spelling of 111111110012113 in words is "one hundred eleven trillion, one hundred eleven billion, one hundred ten million, twelve thousand, one hundred thirteen".
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