Base | Representation |
---|---|
bin | 1010000110110000011110… |
… | …1110011100110111111001 |
3 | 1110100012222022220122022102 |
4 | 2201230013232130313321 |
5 | 2424021224230342103 |
6 | 35344230332033145 |
7 | 2224521066532106 |
oct | 241540756346771 |
9 | 43305868818272 |
10 | 11111210012153 |
11 | 35a4268424069 |
12 | 12b55159027b5 |
13 | 627a2350c684 |
14 | 2a5add333aad |
15 | 144064b18e88 |
hex | a1b07b9cdf9 |
11111210012153 has 2 divisors, whose sum is σ = 11111210012154. Its totient is φ = 11111210012152.
The previous prime is 11111210012087. The next prime is 11111210012207. The reversal of 11111210012153 is 35121001211111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6138144990784 + 4973065021369 = 2477528^2 + 2230037^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111210012153 - 230 = 11110136270329 is a prime.
It is not a weakly prime, because it can be changed into another prime (11111210012953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555605006076 + 5555605006077.
It is an arithmetic number, because the mean of its divisors is an integer number (5555605006077).
Almost surely, 211111210012153 is an apocalyptic number.
It is an amenable number.
11111210012153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111210012153 is an equidigital number, since it uses as much as digits as its factorization.
11111210012153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 20.
Adding to 11111210012153 its reverse (35121001211111), we get a palindrome (46232211223264).
The spelling of 11111210012153 in words is "eleven trillion, one hundred eleven billion, two hundred ten million, twelve thousand, one hundred fifty-three".
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