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11111210041 is a prime number
BaseRepresentation
bin10100101100100011…
…11001110000111001
31001200100200221201211
422112101321300321
5140223432210131
65034315443121
7542226504241
oct122621716071
931610627654
1011111210041
114791a96618
1221a11564a1
131080c946c9
1477597cb21
1545070a5b1
hex296479c39

11111210041 has 2 divisors, whose sum is σ = 11111210042. Its totient is φ = 11111210040.

The previous prime is 11111210009. The next prime is 11111210053. The reversal of 11111210041 is 14001211111.

11111210041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8645094441 + 2466115600 = 92979^2 + 49660^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111210041 - 25 = 11111210009 is a prime.

It is not a weakly prime, because it can be changed into another prime (11111210441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555605020 + 5555605021.

It is an arithmetic number, because the mean of its divisors is an integer number (5555605021).

Almost surely, 211111210041 is an apocalyptic number.

It is an amenable number.

11111210041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111210041 is an equidigital number, since it uses as much as digits as its factorization.

11111210041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 11111210041 its reverse (14001211111), we get a palindrome (25112421152).

The spelling of 11111210041 in words is "eleven billion, one hundred eleven million, two hundred ten thousand, forty-one".