Base | Representation |
---|---|
bin | 1010000110110000011111… |
… | …1110111001011011101001 |
3 | 1110100012222122000200021110 |
4 | 2201230013332321123221 |
5 | 2424021231331322213 |
6 | 35344231004300533 |
7 | 2224521151266330 |
oct | 241540776713351 |
9 | 43305878020243 |
10 | 11111214323433 |
11 | 35a426a8a9204 |
12 | 12b5517241749 |
13 | 627a2438bb23 |
14 | 2a5addb36d17 |
15 | 1440651bb5c3 |
hex | a1b07fb96e9 |
11111214323433 has 16 divisors (see below), whose sum is σ = 16965035006976. Its totient is φ = 6336642527760.
The previous prime is 11111214323411. The next prime is 11111214323497. The reversal of 11111214323433 is 33432341211111.
It is a happy number.
It is not a de Polignac number, because 11111214323433 - 225 = 11111180769001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11111214323433.
It is not an unprimeable number, because it can be changed into a prime (11111214323233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 525939183 + ... + 525960308.
It is an arithmetic number, because the mean of its divisors is an integer number (1060314687936).
Almost surely, 211111214323433 is an apocalyptic number.
It is an amenable number.
11111214323433 is a deficient number, since it is larger than the sum of its proper divisors (5853820683543).
11111214323433 is a wasteful number, since it uses less digits than its factorization.
11111214323433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1051900004.
The product of its digits is 5184, while the sum is 30.
Adding to 11111214323433 its reverse (33432341211111), we get a palindrome (44543555534544).
The spelling of 11111214323433 in words is "eleven trillion, one hundred eleven billion, two hundred fourteen million, three hundred twenty-three thousand, four hundred thirty-three".
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