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11111220073 is a prime number
BaseRepresentation
bin10100101100100011…
…11100001101101001
31001200100201110111101
422112101330031221
5140223433020243
65034320001401
7542226545422
oct122621741551
931610643441
1011111220073
114791aa3108
1221a1160261
131080c99145
14775982649
1545070d54d
hex29647c369

11111220073 has 2 divisors, whose sum is σ = 11111220074. Its totient is φ = 11111220072.

The previous prime is 11111220067. The next prime is 11111220161. The reversal of 11111220073 is 37002211111.

11111220073 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9833300569 + 1277919504 = 99163^2 + 35748^2 .

It is a cyclic number.

It is not a de Polignac number, because 11111220073 - 217 = 11111089001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11111220073.

It is not a weakly prime, because it can be changed into another prime (11111220013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555610036 + 5555610037.

It is an arithmetic number, because the mean of its divisors is an integer number (5555610037).

Almost surely, 211111220073 is an apocalyptic number.

It is an amenable number.

11111220073 is a deficient number, since it is larger than the sum of its proper divisors (1).

11111220073 is an equidigital number, since it uses as much as digits as its factorization.

11111220073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 11111220073 its reverse (37002211111), we get a palindrome (48113431184).

The spelling of 11111220073 in words is "eleven billion, one hundred eleven million, two hundred twenty thousand, seventy-three".