111112210220131 has 2 divisors, whose sum is σ = 111112210220132. Its totient is φ = 111112210220130.

The previous prime is 111112210220059. The next prime is 111112210220149. The reversal of 111112210220131 is 131022012211111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111112210220131 - 2¹¹ = 111112210218083 is a prime.

It is a super-2 number, since 2×111112210220131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111112210220099 and 111112210220108.

It is not a weakly prime, because it can be changed into another prime (111112214220131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556105110065 + 55556105110066.

It is an arithmetic number, because the mean of its divisors is an integer number (55556105110066).

Almost surely, 2^{111112210220131} is an apocalyptic number.

111112210220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

111112210220131 is an equidigital number, since it uses as much as digits as its factorization.

111112210220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 111112210220131 its reverse (131022012211111), we get a palindrome (242134222431242).

The spelling of 111112210220131 in words is "one hundred eleven trillion, one hundred twelve billion, two hundred ten million, two hundred twenty thousand, one hundred thirty-one".