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111113013001 is a prime number
BaseRepresentation
bin110011101111011011…
…0100000011100001001
3101121210122201220011211
41213132312200130021
53310024412404001
6123013345253121
711012325012214
oct1473666403411
9347718656154
10111113013001
1143139443271
121964b6341a1
13a629c85993
145540d4c77b
152d54b9e351
hex19deda0709

111113013001 has 2 divisors, whose sum is σ = 111113013002. Its totient is φ = 111113013000.

The previous prime is 111113012953. The next prime is 111113013017. The reversal of 111113013001 is 100310311111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110247241225 + 865771776 = 332035^2 + 29424^2 .

It is an emirp because it is prime and its reverse (100310311111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111113013001 - 225 = 111079458569 is a prime.

It is a super-2 number, since 2×1111130130012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111113013091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556506500 + 55556506501.

It is an arithmetic number, because the mean of its divisors is an integer number (55556506501).

Almost surely, 2111113013001 is an apocalyptic number.

It is an amenable number.

111113013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113013001 is an equidigital number, since it uses as much as digits as its factorization.

111113013001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 111113013001 its reverse (100310311111), we get a palindrome (211423324112).

The spelling of 111113013001 in words is "one hundred eleven billion, one hundred thirteen million, thirteen thousand, one".