111113014141 has 4 divisors (see below), whose sum is σ = 111114577984. Its totient is φ = 111111450300.

The previous prime is 111113014139. The next prime is 111113014147. The reversal of 111113014141 is 141410311111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141410311111 = 191 ⋅740368121.

It is a cyclic number.

It is not a de Polignac number, because 111113014141 - 2¹ = 111113014139 is a prime.

It is a super-2 number, since 2×111113014141² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111113014147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670005 + ... + 819226.

It is an arithmetic number, because the mean of its divisors is an integer number (27778644496).

Almost surely, 2^111113014141 is an apocalyptic number.

It is an amenable number.

111113014141 is a deficient number, since it is larger than the sum of its proper divisors (1563843).

111113014141 is an equidigital number, since it uses as much as digits as its factorization.

111113014141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1563842.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 111113014141 its reverse (141410311111), we get a palindrome (252523325252).

The spelling of 111113014141 in words is "one hundred eleven billion, one hundred thirteen million, fourteen thousand, one hundred forty-one".