1111131121013 has 4 divisors (see below), whose sum is σ = 1111133741580. Its totient is φ = 1111128500448.

The previous prime is 1111131121003. The next prime is 1111131121033. The reversal of 1111131121013 is 3101211311111.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 785417792644 + 325713328369 = 886238^2 + 570713^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111131121013 is a prime.

It is a super-2 number, since 2×1111131121013² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1111131120982 and 1111131121000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111131121003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512270 + ... + 1576287.

It is an arithmetic number, because the mean of its divisors is an integer number (277783435395).

Almost surely, 2^{1111131121013} is an apocalyptic number.

It is an amenable number.

1111131121013 is a deficient number, since it is larger than the sum of its proper divisors (2620567).

1111131121013 is an equidigital number, since it uses as much as digits as its factorization.

1111131121013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2620566.

The product of its (nonzero) digits is 18, while the sum is 17.

Adding to 1111131121013 its reverse (3101211311111), we get a palindrome (4212342432124).

The spelling of 1111131121013 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, one hundred twenty-one thousand, thirteen".