111113130000 has 200 divisors, whose sum is σ = 362249243136. Its totient is φ = 29336000000.

The previous prime is 111113129999. The next prime is 111113130049. The reversal of 111113130000 is 31311111.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×111113130000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3011665 + ... + 3048335.

Almost surely, 2^111113130000 is an apocalyptic number.

111113130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111113130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (181124621568).

111113130000 is an abundant number, since it is smaller than the sum of its proper divisors (251136113136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111113130000 is a wasteful number, since it uses less digits than its factorization.

111113130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36803 (or 36782 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 111113130000 its reverse (31311111), we get a palindrome (111144441111).

The spelling of 111113130000 in words is "one hundred eleven billion, one hundred thirteen million, one hundred thirty thousand".