Base | Representation |
---|---|
bin | 10000001010110100101… |
… | …000101000010010000011 |
3 | 10221020000201002122120022 |
4 | 100022310220220102003 |
5 | 121201044310041003 |
6 | 2210240321204055 |
7 | 143163614055404 |
oct | 20126450502203 |
9 | 3836021078508 |
10 | 1111132112003 |
11 | 399257123561 |
12 | 15b417a9062b |
13 | 80a191aa7b4 |
14 | 3bac9b279ab |
15 | 1dd82e39738 |
hex | 102b4a28483 |
1111132112003 has 2 divisors, whose sum is σ = 1111132112004. Its totient is φ = 1111132112002.
The previous prime is 1111132111963. The next prime is 1111132112009. The reversal of 1111132112003 is 3002112311111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3002112311111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111132112003 - 236 = 1042412635267 is a prime.
It is a super-2 number, since 2×11111321120032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111132112009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555566056001 + 555566056002.
It is an arithmetic number, because the mean of its divisors is an integer number (555566056002).
Almost surely, 21111132112003 is an apocalyptic number.
1111132112003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111132112003 is an equidigital number, since it uses as much as digits as its factorization.
1111132112003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1111132112003 its reverse (3002112311111), we get a palindrome (4113244423114).
The spelling of 1111132112003 in words is "one trillion, one hundred eleven billion, one hundred thirty-two million, one hundred twelve thousand, three".
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