Base | Representation |
---|---|
bin | 11001010000111010010000… |
… | …101010111100001110011001 |
3 | 112120102022200010022020221111 |
4 | 121100322100222330032121 |
5 | 104030434344131421403 |
6 | 1032152414054140321 |
7 | 32255444310114004 |
oct | 3120722052741631 |
9 | 476368603266844 |
10 | 111113231123353 |
11 | 32449947286a78 |
12 | 105665a43516a1 |
13 | 49ccc182b1ab4 |
14 | 1d61ca273853b |
15 | cca49ba6b56d |
hex | 650e90abc399 |
111113231123353 has 2 divisors, whose sum is σ = 111113231123354. Its totient is φ = 111113231123352.
The previous prime is 111113231123333. The next prime is 111113231123417. The reversal of 111113231123353 is 353321132311111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103813010743689 + 7300220379664 = 10188867^2 + 2701892^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111113231123353 is a prime.
It is not a weakly prime, because it can be changed into another prime (111113231123333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556615561676 + 55556615561677.
It is an arithmetic number, because the mean of its divisors is an integer number (55556615561677).
Almost surely, 2111113231123353 is an apocalyptic number.
It is an amenable number.
111113231123353 is a deficient number, since it is larger than the sum of its proper divisors (1).
111113231123353 is an equidigital number, since it uses as much as digits as its factorization.
111113231123353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860, while the sum is 31.
Adding to 111113231123353 its reverse (353321132311111), we get a palindrome (464434363434464).
The spelling of 111113231123353 in words is "one hundred eleven trillion, one hundred thirteen billion, two hundred thirty-one million, one hundred twenty-three thousand, three hundred fifty-three".
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