Base | Representation |
---|---|
bin | 10000001010110100101… |
… | …100011110101001100001 |
3 | 10221020000202222220211001 |
4 | 100022310230132221201 |
5 | 121201100034333441 |
6 | 2210240354552001 |
7 | 143163625460422 |
oct | 20126454365141 |
9 | 3836022886731 |
10 | 1111133121121 |
11 | 399257752741 |
12 | 15b418298601 |
13 | 80a19471bca |
14 | 3bac9d0b649 |
15 | 1dd83088731 |
hex | 102b4b1ea61 |
1111133121121 has 2 divisors, whose sum is σ = 1111133121122. Its totient is φ = 1111133121120.
The previous prime is 1111133121103. The next prime is 1111133121187. The reversal of 1111133121121 is 1211213311111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1085630628096 + 25502493025 = 1041936^2 + 159695^2 .
It is an emirp because it is prime and its reverse (1211213311111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111133121121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111133121101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555566560560 + 555566560561.
It is an arithmetic number, because the mean of its divisors is an integer number (555566560561).
Almost surely, 21111133121121 is an apocalyptic number.
It is an amenable number.
1111133121121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111133121121 is an equidigital number, since it uses as much as digits as its factorization.
1111133121121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36, while the sum is 19.
Adding to 1111133121121 its reverse (1211213311111), we get a palindrome (2322346432232).
The spelling of 1111133121121 in words is "one trillion, one hundred eleven billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred twenty-one".
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