Base | Representation |
---|---|
bin | 11001010000111010010101… |
… | …100011110000000001010000 |
3 | 112120102022212211121100021111 |
4 | 121100322111203300001100 |
5 | 104030440031124440212 |
6 | 1032152430143503104 |
7 | 32255446324113133 |
oct | 3120722543600120 |
9 | 476368784540244 |
10 | 111113313124432 |
11 | 324499895a4663 |
12 | 105666078b7a94 |
13 | 49ccc2c292c48 |
14 | 1d61cad5a221a |
15 | cca4a3d67ea7 |
hex | 650e958f0050 |
111113313124432 has 40 divisors (see below), whose sum is σ = 215700894385184. Its totient is φ = 55448573307264.
The previous prime is 111113313124399. The next prime is 111113313124453. The reversal of 111113313124432 is 234421313311111.
It is a super-3 number, since 3×1111133131244323 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111113313124394 and 111113313124403.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269268538 + ... + 269680870.
Almost surely, 2111113313124432 is an apocalyptic number.
It is an amenable number.
111113313124432 is a deficient number, since it is larger than the sum of its proper divisors (104587581260752).
111113313124432 is a wasteful number, since it uses less digits than its factorization.
111113313124432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 445067 (or 445061 counting only the distinct ones).
The product of its digits is 5184, while the sum is 31.
Adding to 111113313124432 its reverse (234421313311111), we get a palindrome (345534626435543).
The spelling of 111113313124432 in words is "one hundred eleven trillion, one hundred thirteen billion, three hundred thirteen million, one hundred twenty-four thousand, four hundred thirty-two".
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