11111404813 has 4 divisors (see below), whose sum is σ = 11112061408. Its totient is φ = 11110748220.

The previous prime is 11111404783. The next prime is 11111404817. The reversal of 11111404813 is 31840411111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31840411111 = 43 ⋅740474677.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11111404813 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111404817) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302223 + ... + 336988.

It is an arithmetic number, because the mean of its divisors is an integer number (2778015352).

Almost surely, 2^11111404813 is an apocalyptic number.

It is an amenable number.

11111404813 is a deficient number, since it is larger than the sum of its proper divisors (656595).

11111404813 is an equidigital number, since it uses as much as digits as its factorization.

11111404813 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656594.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 11111404813 its reverse (31840411111), we get a palindrome (42951815924).

The spelling of 11111404813 in words is "eleven billion, one hundred eleven million, four hundred four thousand, eight hundred thirteen".