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111114133423147 is a prime number
BaseRepresentation
bin11001010000111011000110…
…011100111100010000101011
3112120102102000000010211120101
4121100323012130330100223
5104030443221124020042
61032153043405410231
732255505544411441
oct3120730634742053
9476372000124511
10111114133423147
113244a26a63a188
12105667b6569977
134a000302021ba
141d61d4a4d2b91
15cca500d9e6b7
hex650ec673c42b

111114133423147 has 2 divisors, whose sum is σ = 111114133423148. Its totient is φ = 111114133423146.

The previous prime is 111114133423129. The next prime is 111114133423169. The reversal of 111114133423147 is 741324331411111.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111114133423147 is a prime.

It is not a weakly prime, because it can be changed into another prime (111114133429147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55557066711573 + 55557066711574.

It is an arithmetic number, because the mean of its divisors is an integer number (55557066711574).

Almost surely, 2111114133423147 is an apocalyptic number.

111114133423147 is a deficient number, since it is larger than the sum of its proper divisors (1).

111114133423147 is an equidigital number, since it uses as much as digits as its factorization.

111114133423147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24192, while the sum is 37.

Adding to 111114133423147 its reverse (741324331411111), we get a palindrome (852438464834258).

The spelling of 111114133423147 in words is "one hundred eleven trillion, one hundred fourteen billion, one hundred thirty-three million, four hundred twenty-three thousand, one hundred forty-seven".