Base | Representation |
---|---|
bin | 10000001010110101001… |
… | …111111000000001010011 |
3 | 10221020001102110100011022 |
4 | 100022311033320001103 |
5 | 121201104423300313 |
6 | 2210241325510055 |
7 | 143164100364662 |
oct | 20126517700123 |
9 | 3836042410138 |
10 | 1111142400083 |
11 | 399261a10101 |
12 | 15b41b41232b |
13 | 80a1b370511 |
14 | 3bacb244dd9 |
15 | 1dd83cbcc08 |
hex | 102b53f8053 |
1111142400083 has 2 divisors, whose sum is σ = 1111142400084. Its totient is φ = 1111142400082.
The previous prime is 1111142400073. The next prime is 1111142400127. The reversal of 1111142400083 is 3800042411111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111142400083 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111142400073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555571200041 + 555571200042.
It is an arithmetic number, because the mean of its divisors is an integer number (555571200042).
Almost surely, 21111142400083 is an apocalyptic number.
1111142400083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111142400083 is an equidigital number, since it uses as much as digits as its factorization.
1111142400083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 26.
Adding to 1111142400083 its reverse (3800042411111), we get a palindrome (4911184811194).
The spelling of 1111142400083 in words is "one trillion, one hundred eleven billion, one hundred forty-two million, four hundred thousand, eighty-three".
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