Base | Representation |
---|---|
bin | 10000001010111000101… |
… | …100010111010101000011 |
3 | 10221020012110012212202002 |
4 | 100022320230113111003 |
5 | 121201214222400003 |
6 | 2210251152414215 |
7 | 143165401566605 |
oct | 20127054272503 |
9 | 3836173185662 |
10 | 1111200200003 |
11 | 3992915a9033 |
12 | 15b43684736b |
13 | 80a2a329c5a |
14 | 3bad4bad175 |
15 | 1dd88dd8a88 |
hex | 102b8b17543 |
1111200200003 has 2 divisors, whose sum is σ = 1111200200004. Its totient is φ = 1111200200002.
The previous prime is 1111200199973. The next prime is 1111200200021. The reversal of 1111200200003 is 3000020021111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111200200003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111200200303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555600100001 + 555600100002.
It is an arithmetic number, because the mean of its divisors is an integer number (555600100002).
Almost surely, 21111200200003 is an apocalyptic number.
1111200200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111200200003 is an equidigital number, since it uses as much as digits as its factorization.
1111200200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 1111200200003 its reverse (3000020021111), we get a palindrome (4111220221114).
The spelling of 1111200200003 in words is "one trillion, one hundred eleven billion, two hundred million, two hundred thousand, three".
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