Base | Representation |
---|---|
bin | 1010000110110011011100… |
… | …0000101011100011001110 |
3 | 1110100022000121122212010001 |
4 | 2201230313000223203032 |
5 | 2424024340322220024 |
6 | 35344441151234514 |
7 | 2224546541534032 |
oct | 241546700534316 |
9 | 43308017585101 |
10 | 11112003320014 |
11 | 35a4635203aa3 |
12 | 12b56b7518a3a |
13 | 627b1b98b4cc |
14 | 2a5b7683a1c2 |
15 | 1440ae5bd244 |
hex | a1b3702b8ce |
11112003320014 has 4 divisors (see below), whose sum is σ = 16668004980024. Its totient is φ = 5556001660006.
The previous prime is 11112003320003. The next prime is 11112003320021. The reversal of 11112003320014 is 41002330021111.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11112003319973 and 11112003320000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2778000830002 + ... + 2778000830005.
It is an arithmetic number, because the mean of its divisors is an integer number (4167001245006).
Almost surely, 211112003320014 is an apocalyptic number.
11112003320014 is a deficient number, since it is larger than the sum of its proper divisors (5556001660010).
11112003320014 is an equidigital number, since it uses as much as digits as its factorization.
11112003320014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5556001660009.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11112003320014 its reverse (41002330021111), we get a palindrome (52114333341125).
The spelling of 11112003320014 in words is "eleven trillion, one hundred twelve billion, three million, three hundred twenty thousand, fourteen".
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