Base | Representation |
---|---|
bin | 11001010001000000101010… |
… | …001001011110111100101011 |
3 | 112120102222101220012201110201 |
4 | 121101000222021132330223 |
5 | 104031042431324324433 |
6 | 1032155511503453031 |
7 | 32256106456154452 |
oct | 3121005211367453 |
9 | 476388356181421 |
10 | 111120101011243 |
11 | 32451852142475 |
12 | 105679a0bb7177 |
13 | 4a0077166020c |
14 | 1d62354ca5b99 |
15 | cca74ec33a7d |
hex | 65102a25ef2b |
111120101011243 has 2 divisors, whose sum is σ = 111120101011244. Its totient is φ = 111120101011242.
The previous prime is 111120101011193. The next prime is 111120101011277. The reversal of 111120101011243 is 342110101021111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111120101011243 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111120101011243.
It is not a weakly prime, because it can be changed into another prime (111120101911243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560050505621 + 55560050505622.
It is an arithmetic number, because the mean of its divisors is an integer number (55560050505622).
Almost surely, 2111120101011243 is an apocalyptic number.
111120101011243 is a deficient number, since it is larger than the sum of its proper divisors (1).
111120101011243 is an equidigital number, since it uses as much as digits as its factorization.
111120101011243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 111120101011243 its reverse (342110101021111), we get a palindrome (453230202032354).
The spelling of 111120101011243 in words is "one hundred eleven trillion, one hundred twenty billion, one hundred one million, eleven thousand, two hundred forty-three".
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