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111120109993 is a prime number
BaseRepresentation
bin110011101111101000…
…1100101000110101001
3101121211011002110102101
41213133101211012221
53310033222004433
6123014201333401
711012442231154
oct1473721450651
9347734073371
10111120109993
1143142450352
1219651a97261
13a62b59c099
145541c78c9b
152d5560207d
hex19df4651a9

111120109993 has 2 divisors, whose sum is σ = 111120109994. Its totient is φ = 111120109992.

The previous prime is 111120109939. The next prime is 111120110011. The reversal of 111120109993 is 399901021111.

Together with previous prime (111120109939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88478287209 + 22641822784 = 297453^2 + 150472^2 .

It is an emirp because it is prime and its reverse (399901021111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111120109993 - 233 = 102530175401 is a prime.

It is not a weakly prime, because it can be changed into another prime (111120109193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560054996 + 55560054997.

It is an arithmetic number, because the mean of its divisors is an integer number (55560054997).

Almost surely, 2111120109993 is an apocalyptic number.

It is an amenable number.

111120109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

111120109993 is an equidigital number, since it uses as much as digits as its factorization.

111120109993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4374, while the sum is 37.

The spelling of 111120109993 in words is "one hundred eleven billion, one hundred twenty million, one hundred nine thousand, nine hundred ninety-three".