Base | Representation |
---|---|
bin | 10000001010111000110… |
… | …011010110110111100001 |
3 | 10221020012120200000022100 |
4 | 100022320303112313201 |
5 | 121201220210024441 |
6 | 2210251300001013 |
7 | 143165423303145 |
oct | 20127063266741 |
9 | 3836176600270 |
10 | 1111202033121 |
11 | 399292640304 |
12 | 15b437390169 |
13 | 80a2a81c43b |
14 | 3bad5129225 |
15 | 1dd8914bcb6 |
hex | 102b8cd6de1 |
1111202033121 has 48 divisors (see below), whose sum is σ = 1647747459072. Its totient is φ = 721220220000.
The previous prime is 1111202033119. The next prime is 1111202033219. The reversal of 1111202033121 is 1213302021111.
1111202033121 is a `hidden beast` number, since 1 + 111 + 202 + 0 + 331 + 21 = 666.
It is not a de Polignac number, because 1111202033121 - 21 = 1111202033119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1111202033094 and 1111202033103.
It is not an unprimeable number, because it can be changed into a prime (1111202033021) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 163625236 + ... + 163632026.
It is an arithmetic number, because the mean of its divisors is an integer number (34328072064).
Almost surely, 21111202033121 is an apocalyptic number.
It is an amenable number.
1111202033121 is a deficient number, since it is larger than the sum of its proper divisors (536545425951).
1111202033121 is a wasteful number, since it uses less digits than its factorization.
1111202033121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8154 (or 8151 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1111202033121 its reverse (1213302021111), we get a palindrome (2324504054232).
The spelling of 1111202033121 in words is "one trillion, one hundred eleven billion, two hundred two million, thirty-three thousand, one hundred twenty-one".
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