1111212433 has 2 divisors, whose sum is σ = 1111212434. Its totient is φ = 1111212432.

The previous prime is 1111212419. The next prime is 1111212439. The reversal of 1111212433 is 3342121111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1101775249 + 9437184 = 33193^2 + 3072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111212433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1111212433.

It is not a weakly prime, because it can be changed into another prime (1111212439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555606216 + 555606217.

It is an arithmetic number, because the mean of its divisors is an integer number (555606217).

Almost surely, 2^1111212433 is an apocalyptic number.

It is an amenable number.

1111212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111212433 is an equidigital number, since it uses as much as digits as its factorization.

1111212433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 1111212433 is about 33334.8531270201. The cubic root of 1111212433 is about 1035.7756507610.

Adding to 1111212433 its reverse (3342121111), we get a palindrome (4453333544).

The spelling of 1111212433 in words is "one billion, one hundred eleven million, two hundred twelve thousand, four hundred thirty-three".