Base | Representation |
---|---|
bin | 11001010001000001110011… |
… | …011110000000111010010001 |
3 | 112120110002120121220020011201 |
4 | 121101001303132000322101 |
5 | 104031102441232130001 |
6 | 1032200233525311201 |
7 | 32256152114044513 |
oct | 3121016336007221 |
9 | 476402517806151 |
10 | 111121331130001 |
11 | 3245232354a945 |
12 | 10568084b65501 |
13 | 4a0090946b73a |
14 | 1d624303d5bb3 |
15 | cca7c2c1d501 |
hex | 651073780e91 |
111121331130001 has 2 divisors, whose sum is σ = 111121331130002. Its totient is φ = 111121331130000.
The previous prime is 111121331129981. The next prime is 111121331130031. The reversal of 111121331130001 is 100031133121111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91196311704976 + 19925019425025 = 9549676^2 + 4463745^2 .
It is a cyclic number.
It is not a de Polignac number, because 111121331130001 - 27 = 111121331129873 is a prime.
It is not a weakly prime, because it can be changed into another prime (111121331130031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560665565000 + 55560665565001.
It is an arithmetic number, because the mean of its divisors is an integer number (55560665565001).
Almost surely, 2111121331130001 is an apocalyptic number.
It is an amenable number.
111121331130001 is a deficient number, since it is larger than the sum of its proper divisors (1).
111121331130001 is an equidigital number, since it uses as much as digits as its factorization.
111121331130001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 111121331130001 its reverse (100031133121111), we get a palindrome (211152464251112).
The spelling of 111121331130001 in words is "one hundred eleven trillion, one hundred twenty-one billion, three hundred thirty-one million, one hundred thirty thousand, one".
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