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11112308503 = 88712527969
BaseRepresentation
bin10100101100101100…
…00101111100010111
31001200102202202112121
422112112011330113
5140224222333003
65034355200411
7542242030612
oct122626057427
931612682477
1011112308503
11479267693a
1221a15a6107
13108128a69a
14775b87179
15450875cbd
hex296585f17

11112308503 has 4 divisors (see below), whose sum is σ = 11124837360. Its totient is φ = 11099779648.

The previous prime is 11112308483. The next prime is 11112308509. The reversal of 11112308503 is 30580321111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11112308503 - 29 = 11112307991 is a prime.

It is a super-2 number, since 2×111123085032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11112308509) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6263098 + ... + 6264871.

It is an arithmetic number, because the mean of its divisors is an integer number (2781209340).

Almost surely, 211112308503 is an apocalyptic number.

11112308503 is a deficient number, since it is larger than the sum of its proper divisors (12528857).

11112308503 is an equidigital number, since it uses as much as digits as its factorization.

11112308503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12528856.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 11112308503 its reverse (30580321111), we get a palindrome (41692629614).

The spelling of 11112308503 in words is "eleven billion, one hundred twelve million, three hundred eight thousand, five hundred three".

Divisors: 1 887 12527969 11112308503