Base | Representation |
---|---|
bin | 1010000110110100100101… |
… | …1110000011011101010011 |
3 | 1110100022211012101201220122 |
4 | 2201231021132003131103 |
5 | 2424031004112310003 |
6 | 35344532013100455 |
7 | 2224560322052222 |
oct | 241551136033523 |
9 | 43308735351818 |
10 | 11112313010003 |
11 | 35a4783aa6737 |
12 | 12b578318772b |
13 | 627b6ab9ca1a |
14 | 2a5ba5a12cb9 |
15 | 1440cb893238 |
hex | a1b49783753 |
11112313010003 has 2 divisors, whose sum is σ = 11112313010004. Its totient is φ = 11112313010002.
The previous prime is 11112313009913. The next prime is 11112313010011. The reversal of 11112313010003 is 30001031321111.
11112313010003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112313010003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11112313310003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556156505001 + 5556156505002.
It is an arithmetic number, because the mean of its divisors is an integer number (5556156505002).
Almost surely, 211112313010003 is an apocalyptic number.
11112313010003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112313010003 is an equidigital number, since it uses as much as digits as its factorization.
11112313010003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11112313010003 its reverse (30001031321111), we get a palindrome (41113344331114).
The spelling of 11112313010003 in words is "eleven trillion, one hundred twelve billion, three hundred thirteen million, ten thousand, three".
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