Base | Representation |
---|---|
bin | 10000001010111010100… |
… | …101101101111011100011 |
3 | 10221020021200002002121022 |
4 | 100022322211231323203 |
5 | 121201300343341003 |
6 | 2210254250320055 |
7 | 143166236153141 |
oct | 20127245557343 |
9 | 3836250062538 |
10 | 1111232012003 |
11 | 3992a8556943 |
12 | 15b44542902b |
13 | 80a33ab7919 |
14 | 3bad90d0591 |
15 | 1dd8babe738 |
hex | 102ba96dee3 |
1111232012003 has 2 divisors, whose sum is σ = 1111232012004. Its totient is φ = 1111232012002.
The previous prime is 1111232011913. The next prime is 1111232012027. The reversal of 1111232012003 is 3002102321111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111232012003 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111232012203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555616006001 + 555616006002.
It is an arithmetic number, because the mean of its divisors is an integer number (555616006002).
Almost surely, 21111232012003 is an apocalyptic number.
1111232012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111232012003 is an equidigital number, since it uses as much as digits as its factorization.
1111232012003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1111232012003 its reverse (3002102321111), we get a palindrome (4113334333114).
The spelling of 1111232012003 in words is "one trillion, one hundred eleven billion, two hundred thirty-two million, twelve thousand, three".
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