11113004041 has 2 divisors, whose sum is σ = 11113004042. Its totient is φ = 11113004040.

The previous prime is 11113004009. The next prime is 11113004081. The reversal of 11113004041 is 14040031111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11108316816 + 4687225 = 105396^2 + 2165^2 .

It is a cyclic number.

It is not a de Polignac number, because 11113004041 - 2⁵ = 11113004009 is a prime.

It is not a weakly prime, because it can be changed into another prime (11113004081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556502020 + 5556502021.

It is an arithmetic number, because the mean of its divisors is an integer number (5556502021).

Almost surely, 2^11113004041 is an apocalyptic number.

It is an amenable number.

11113004041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11113004041 is an equidigital number, since it uses as much as digits as its factorization.

11113004041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11113004041 its reverse (14040031111), we get a palindrome (25153035152).

The spelling of 11113004041 in words is "eleven billion, one hundred thirteen million, four thousand, forty-one".