Base | Representation |
---|---|
bin | 10000001010111111010… |
… | …111001110111011111000 |
3 | 10221020111020210001012121 |
4 | 100022333113032323320 |
5 | 121201431344213422 |
6 | 2210310231051024 |
7 | 143201231000113 |
oct | 20127727167370 |
9 | 3836436701177 |
10 | 1111312101112 |
11 | 399339788a94 |
12 | 15b468210a74 |
13 | 80a47579725 |
14 | 3bb059bb57a |
15 | 1dd93b3e8c7 |
hex | 102bf5ceef8 |
1111312101112 has 16 divisors (see below), whose sum is σ = 2084603370840. Its totient is φ = 555417868896.
The previous prime is 1111312101091. The next prime is 1111312101157. The reversal of 1111312101112 is 2111012131111.
It is a super-2 number, since 2×11113121011122 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29752878 + ... + 29790205.
Almost surely, 21111312101112 is an apocalyptic number.
It is an amenable number.
1111312101112 is a deficient number, since it is larger than the sum of its proper divisors (973291269728).
1111312101112 is a wasteful number, since it uses less digits than its factorization.
1111312101112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59545422 (or 59545418 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 16.
Adding to 1111312101112 its reverse (2111012131111), we get a palindrome (3222324232223).
Subtracting 1111312101112 from its reverse (2111012131111), we obtain a cube (999700029999 = 99993).
The spelling of 1111312101112 in words is "one trillion, one hundred eleven billion, three hundred twelve million, one hundred one thousand, one hundred twelve".
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