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11113140022 = 25556570011
BaseRepresentation
bin10100101100110010…
…10000111100110110
31001200111100000011121
422112121100330312
5140224430440042
65034425054154
7542252063065
oct122631207466
931614300147
1011113140022
114793094646
1221a192735a
1310814bbcca
14775d221dc
1545098c367
hex296650f36

11113140022 has 4 divisors (see below), whose sum is σ = 16669710036. Its totient is φ = 5556570010.

The previous prime is 11113140013. The next prime is 11113140037. The reversal of 11113140022 is 22004131111.

11113140022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×111131400222 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11113139978 and 11113140005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2778285004 + ... + 2778285007.

It is an arithmetic number, because the mean of its divisors is an integer number (4167427509).

Almost surely, 211113140022 is an apocalyptic number.

11113140022 is a deficient number, since it is larger than the sum of its proper divisors (5556570014).

11113140022 is an equidigital number, since it uses as much as digits as its factorization.

11113140022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5556570013.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11113140022 its reverse (22004131111), we get a palindrome (33117271133).

The spelling of 11113140022 in words is "eleven billion, one hundred thirteen million, one hundred forty thousand, twenty-two".

Divisors: 1 2 5556570011 11113140022