Base | Representation |
---|---|
bin | 10100101100110011… |
… | …11110001100010010 |
3 | 1001200111200102100212 |
4 | 22112121332030102 |
5 | 140230002402310 |
6 | 5034433044122 |
7 | 542253464252 |
oct | 122631761422 |
9 | 31614612325 |
10 | 11113325330 |
11 | 4793200898 |
12 | 21a19b6642 |
13 | 1081555463 |
14 | 775d6d962 |
15 | 4509c7205 |
hex | 29667e312 |
11113325330 has 16 divisors (see below), whose sum is σ = 20126712384. Its totient is φ = 4418057520.
The previous prime is 11113325297. The next prime is 11113325369. The reversal of 11113325330 is 3352331111.
11113325330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11113325296 and 11113325305.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3407366 + ... + 3410625.
It is an arithmetic number, because the mean of its divisors is an integer number (1257919524).
Almost surely, 211113325330 is an apocalyptic number.
11113325330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11113325330 is a deficient number, since it is larger than the sum of its proper divisors (9013387054).
11113325330 is a wasteful number, since it uses less digits than its factorization.
11113325330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6818161.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 11113325330 its reverse (3352331111), we get a palindrome (14465656441).
The spelling of 11113325330 in words is "eleven billion, one hundred thirteen million, three hundred twenty-five thousand, three hundred thirty".
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