Base | Representation |
---|---|
bin | 10100101100110011… |
… | …11111101000100001 |
3 | 1001200111200201110111 |
4 | 22112121333220201 |
5 | 140230003044413 |
6 | 5034433131321 |
7 | 542253520414 |
oct | 122631775041 |
9 | 31614621414 |
10 | 11113331233 |
11 | 4793205274 |
12 | 21a19b9b41 |
13 | 1081558054 |
14 | 775d71b7b |
15 | 4509c8d3d |
hex | 29667fa21 |
11113331233 has 2 divisors, whose sum is σ = 11113331234. Its totient is φ = 11113331232.
The previous prime is 11113331227. The next prime is 11113331237. The reversal of 11113331233 is 33213331111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5884884369 + 5228446864 = 76713^2 + 72308^2 .
It is an emirp because it is prime and its reverse (33213331111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11113331233 is a prime.
It is a super-2 number, since 2×111133312332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11113331237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556665616 + 5556665617.
It is an arithmetic number, because the mean of its divisors is an integer number (5556665617).
Almost surely, 211113331233 is an apocalyptic number.
It is an amenable number.
11113331233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113331233 is an equidigital number, since it uses as much as digits as its factorization.
11113331233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 486, while the sum is 22.
Adding to 11113331233 its reverse (33213331111), we get a palindrome (44326662344).
The spelling of 11113331233 in words is "eleven billion, one hundred thirteen million, three hundred thirty-one thousand, two hundred thirty-three".
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