Base | Representation |
---|---|
bin | 10100101100110011… |
… | …11111101001100101 |
3 | 1001200111200201120000 |
4 | 22112121333221211 |
5 | 140230003100201 |
6 | 5034433131513 |
7 | 542253520542 |
oct | 122631775145 |
9 | 31614621500 |
10 | 11113331301 |
11 | 4793205326 |
12 | 21a19b9b99 |
13 | 10815580a7 |
14 | 775d71bc9 |
15 | 4509c8d86 |
hex | 29667fa65 |
11113331301 has 40 divisors (see below), whose sum is σ = 17033400384. Its totient is φ = 7216672320.
The previous prime is 11113331269. The next prime is 11113331311. The reversal of 11113331301 is 10313331111.
It is not a de Polignac number, because 11113331301 - 25 = 11113331269 is a prime.
It is a super-2 number, since 2×111133313012 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11113331311) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2412066 + ... + 2416668.
Almost surely, 211113331301 is an apocalyptic number.
It is an amenable number.
11113331301 is a deficient number, since it is larger than the sum of its proper divisors (5920069083).
11113331301 is an equidigital number, since it uses as much as digits as its factorization.
11113331301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5383 (or 5374 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 11113331301 its reverse (10313331111), we get a palindrome (21426662412).
The spelling of 11113331301 in words is "eleven billion, one hundred thirteen million, three hundred thirty-one thousand, three hundred one".
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